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IBM DB2 9.7 Advanced DBA for LUW Sample Questions:

1. If table space TBSP1 is using automatic storage, and the existing storage paths are full, which command would increase the available storage?

A) ALTER DATABASE ADD STORAGE FOR tbsp1 ('/db2/filesystem1')
B) ALTER DATABASE ADD STORAGE ON '/db2/filesystem1'
C) ALTER TABLESPACE tbsp1 EXTEND USING ('/db2/filesystem1')
D) ALTER TABLESPACE tbsp1 ADD ('/db2/filesystem1')

2. A table named TAB_A was created with the COMPRESS YES option specified and populated with 100,000 rows. If a DBA wants to create an index on table TAB_A, which statement is true?

A) The index will automatically be compressed since the table it is associated with is compressed; the ALTER INDEX command does not have to be executed.
B) In order for the index to be compressed, it must be enabled for compression by specifying the COMPRESS YES option with the CREATE INDEX statement that is used to create it.
C) In order for the index to be compressed, it must be enabled for compression by specifying the COMPRESS YES option in the CREATE INDEX statement used to create it; however, the index will not be compressed until the ALTER INDEX command is used to create an index compression dictionary.
D) The index will automatically be enabled for compression because the associated table is compressed; however, the index will not be compressed until it is REORGed.

3. What is the minimum authority required to execute the LOAD command?

A) DATAACCESS
B) SQLADM
C) SYSCTRL
D) ACCESSCTRL

4. Which option of the ALTER TABLE statement tells the DB2 optimizer to use an index scan on a table that might vary in size at run time from being empty to containing a large number of rows?

A) VOLATILE
B) INDEXSCAN
C) CARDINALITY VOLATILE
D) CURRENT CARDINALITY

5. Table TAB1 was created using the following statement:
CREATE TABLE tab1 (c1 INT, c2 INT, c3 INT, c4 INT, c5 INT);
If column C1 is unique and queries typically access columns C1, C2 and C3 together, which statement(s) will create index(es) that will provide optimal query performance?

A) CREATE UNIQUE INDEX xtab1 ON tab1 (c1); CREATE INDEX xtab2 ON tab1 (c2) INCLUDE (c3);
B) CREATE UNIQUE INDEX xtab1 ON tab1 (c1) INCLUDE (c2, c3);
C) CREATE UNIQUE INDEX xtab1 ON tab1 (c2) INCLUDE (c1, c3);
D) CREATE UNIQUE INDEX xtab1 ON tab1 (c3, c2, c1);

Solutions: